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(A) When three coins are tossed once,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$Therefore,the total number of po

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$1/8$

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(A) When three coins are tossed once,the sample space $S$ is given by:$S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$Therefore,the total number of possible outcomes is $n(S) = 8$.Let $F$ be the event of getting no head. The only outcome corresponding to this event is:$F = \{TTT\}$Thus,the number of favourable outcomes is $n(F) = 1$.The probability of event $F$ is given by:$P(F) = \frac{n(F)}{n(S)} = \frac{1}{8}$

Three coins are tossed once. Find the probability of getting no head.

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